Seeking help with a curl command in a bash script - SOLVED
Seeking help with a curl command in a bash script - SOLVED
I've got this command in a bash script:
TEST=$(curl -o /dev/null -s -k -w "%{http_code}" -u "${USERNAME}:${PASSWORD}" "${URL}/dashboard/")
echo "${TEST}" #debug
When the script runs, the output is "000".
When I run the same curl command from the shell, the output is "200" (which is correct, since the URL is valid).
I verified that the USERNAME, PASSWORD, and URL vars are being passed to the subshell.
I'd appreciate it if you could point out what I'm doing wrong here. :)
UPDATE: This has been solved.
I love bash's -x option for exactly this type of debugging. It prints out every command before running it, so you can see what is different about the command as the script is running it
bash -x my-script.shOff the top of my head, I'm guessing the inline shell command $( ... ) is eating your double quotes, and I bet you should escape them, particularly around username and password
Thanks for the suggestion.
set -xdidn't reveal any errors, and the commands that it'the script is executing are as I expect them to be.I did just discover, though, a possible cause for my issue: https://lemmy.thewooskeys.com/comment/520854
Add echo before your curl command to see what the expanded command line actually is. Perhaps the arguments aren't as you expect them
Thanks for the suggestion. I already tried this: echo-ed the curl command to stdout and then in the shell copied it and pasted it to run it. From the script I get "000", from the shell I get "200".
what happens when you wrap $() in quotes?
Thanks for the suggestion. I just tried it and the result is the same. :(
What exit code so you get from curl?
Ah!
TEST=$(curl -o /dev/null -s -k -w "%{http_code}" -u "${USERNAME}:${PASSWORD}" "${URL}/dashboard/#/http/routers") echo "previous exit code: $?" #debug echo "${TEST}" #debugThis outputs:
previous exit code: 7 000Is
$?referring to the exit command of the curl in the subshell? Or is it referring to the assignment of the subshell's output to the TEST var?
I verified that the USERNAME, PASSWORD, and URL vars are being passed to the subshell.
But are they being passed into the script? Normal behavior would be for variables to propagate to subshells but not to scripts/commands, unless you explicitly export them (e.g.
export USERNAME='my_username'instead of justUSERNAME='my_username'). Is that what's happening here?Another possibility is that when the script runs, it is run with a different shell, like sh or zsh. Does your script have a #! line at the top, and is it pointing to the same version of
bashyou are running in Terminal?If you run
echo $PATH; which curlin the script vs directly in your Terminal, do they output the same results? This is a bit of an edge case, but I've been stymied before by having multiple versions of curl installed (e.g. via homebrew and via my distro) and different PATHs in different contexts causing unexpected behavior.