Do you know the answer?

0%
The only winning move is not to choose

If you're choosing the answer, then there is 100% chance of being correct. Since none of these answers is 100%, the chance is 0%.
- That logic would only hold if I wasn't dumb as rocks.
- 🤯

Thanks for making me laugh all alone in my car before heading in to work. I wish I could give you an award. Cheers!

This is a conundrum wrapped in a turducken, swaddled in nesting dolls.
- lol chill out there buddy it is only self-referential once. maybe twice.
  
  I'm not certain, I think it's an infinite loop.
  I.E. If the answer is 25%, you have a 50% chance, if the answer is 50%, you have a 25% chance, if the answer is 25%, you have a 50% chance...

It's annoying that 25% appears twice. How about these answers:
a) 100%
b) 75%
c) 50%
d) 0%

What's the correct value if the answer is not picked at random but the test takers can choose freely?
- All answers are correct then.

It's probably graded by a computer, and a) or d) is a fake answer, since the automated system doesn't support multiple right answers.
I'm going to go with 25% chance if picking random, and a 50% chance if picking between a) and d).
If it's graded by a human, the correct answer is f) + u)
- Many systems do allow multiple correct answers.

The question is malformed and the correct answer isn't listed in the multiple choices. Therefore the correct answer is 0%
- If only one of the 4 options said 25% would it still be malformed#

42
- Damn hitchhikers.
- But what's the question?
  
  how many roads must a man walk down?
  
  What is six times nine

B.
This is a multiple choice test. Once you eliminate three answers, you pick the fourth answer and move on to the next question. It can't be A, C, or D, for reasons that I understand. There's a non-zero chance that it's B for a reason that I don't understand.
If there is no correct answer, then there's no point hemming and hawing about it.
B. Final answer.
- I love this, it shows how being good at (multiple choice) tests doesn't mean you're good at the topic. I'm not good at tests because my country's education system priorities understanding and problem solving. That's why we fail at PISA
- Entertaining response but I disagree.
  I'm going to say that unless you're allowed to select more than one answer, the correct answer is 25%. That's either a or d.
  By doing something other than guessing randomly (seeing that 1 in 4 is 25% and that this answer appears twice), you now have a 50% chance of getting the answer correct. However, that doesn't change the premise that 1 in 4 answers is correct. It's still 25%, a or d.
  
  That's an interesting perspective. The odds of correctly guessing any multiple choice question with four answers should be 25%. But that assumes no duplicate answers, so I still say that's wrong.
- You think like I do. Bet you test well.
- You chose A, C, and D, so you have a 100% chance.
- Nice logic; poor reading comprehension.
  
  Does better reading comprehension get you a better answer?

This is a self-referential paradox — a classic logic puzzle designed to be tricky. Let’s break it down:
Step-by-step analysis:
How many choices? There are 4 possible answers, so if we pick one randomly, the chance of picking any specific one is 1 in 4 = 25%.
How many answers say “25%”? Two.
That means the probability of randomly choosing an answer that says “25%” is 2 in 4 = 50%.
But if the correct answer is 50%, then only one option says “50%” — which is (c). So the probability of picking it at random is 1 in 4 = 25%, contradicting the idea that 50% is correct.
If the correct answer is 25%, then two options say that — a and d. So the chance of picking one of those at random is 50%, not 25% — again a contradiction.
Similarly, if 60% is correct (only one option), then the chance of picking it randomly is 25%, which again makes it incorrect.
Conclusion: Any choice leads to a contradiction. This is a self-referential paradox, meaning the question breaks logical consistency. There is no consistent correct answer.
- Chatgpt ass answer lmao
  
  haha yeah, I knew it at the "let's break it down:"
  I was like.. I know this voice....
  
  Got it right though
  
  The © gave it away
- ^{dontthinkaboutitdontthinkaboutitdontthinkaboutit}
- ...so like, which one you picking?
  
  E.
- I would think that if you truly pick at random, it's still a 25% chance no matter how you cut it
- ©
  You had to show off, huh
  
  The comment - which isn't edited - uses (c).
  Whatever client you use replaces/renders (c) [bracket c bracket] as ©.
  
  (tm)

C, which means A or D, which means C, which means...
- Lisa stays home?

33% innit
- iis
- It is 33% if the answer itself is randomly chosen from 25%, 50%, and 60%. Then you have:
  If the answer is 25%: A 1/2 chance of guessing right
  If the answer is 50%: A 1/4 chance of guessing right
  If the answer is 60%: A 1/4 chance of guessing right
  And 1/31/2 + 1/31/4 + 1/31/4 = 1/3, or 33.333...% chance
  If the answer is randomly chosen from A, B, C, and D (With A or D being picked meaning D or A are also good, so 25% has a 50% chance of being the answer) then your probability of being right changes to 37.5%.
  This would hold up if the question were less purposely obtuse, like asking "What would be the probability of answering the following question correctly if guessing from A, B, C and D randomly, if its answer were also chosen from A, B, C and D at random?", with the choices being something like "A: A or D, B: B, C: C, D: A or D"

Paradoxes aside, if you're given multiple choices without the guarantee that any of them are correct, you can't assign a chance of picking the right one at random anyway.

It's 0%, because 0% isn't on the list and therefore you have no chance of picking it. It's the only answer consistent with itself. All other chances cause a kind of paradox-loop.
- I agree with 0% but disagree there's any paradox - every choice is just plain old wrong. Each choice cannot be correct because no percentage reflects the chance of picking that number.
  Ordinarily we'd assume the chance is 25% because in most tests there's only one right choice. But this one evidently could have more than one right choice, if the choice stated twice was correct - which it isn't. So there's no basis for supposing that 25% is correct here, which causes the whole paradox to unravel.
  Now replace 60% with 0%. Maybe that would count as a proper paradox. But I'd still say not really, the answer is 0% - it's just wrong in the hypothetical situation posed by the question rather than the actual question.
- Correct - even if you include the (necessary) option of making up your own answer. If you pick a percentage at random, you have a 0% chance of picking 0%.

This is a paradox, and I don't think there is a correct answer, at least not as a letter choice. The correct answer is to explain the paradox.
- You can rationalize your way to exclude all but a last answer, there by making it the right answer.
  Like, seeing as there are two 25% options, so there aren't four different answers, which means there isn't a 25% chance. This lead to there only being two options left 50% or 60%. This would seem to make 50% the right answer, but it's not, because you know the options, so it's not random, which in turn means you're not guessing. So you have more that 50% chance of choosing the right answer. So 60% is the closest to a right answer, by bullshitting and gaslighting yourself into thinking you solved question.
  
  Having been to school I know a teacher did not read this question so tge answer is probably A, B, C, or D. Chosen randomly of course. But you will get credit for 3/4 answers as long as you take the time to talk to the teacher during office hours.

I see 25% twice so my bet is on 50%.
- But 50% only appears once, which would make the answer 25%.

This seems like a version of the Liar paradox. Assume "this statement is false" is true. Is the statement true or false?
There are a bunch of ways to break the paradox, but they all require using a system that doesn't allow it to exist. For example, a system where truth is a percentage so a statement being 50% true is allowed.
For this question, one way to break the paradox would be to say that multiple choice answers must all be unique and repeated answers are ignored. Using that rule, this question only has the answers a) 25%, b) 60%, and c) 50%, and none of them are correct. There's a 0% chance of getting the correct answer.

50/50, you either guess it right or you dont

If you suppose a multiple choice test MUST ONLY have one correct answer:
Eliminate duplicate 25% answers
You are left with 60% and 50% as potential answers to this question.
C is the answer
If you were to actually select an answer at random to this question while believing the above, you would have a 50% chance of answering 25%.
It is obvious to postulate that: for all multiple choice questions with no duplicate answers, there is a 25% chance of selecting the correct answer.
However as you can see, in order to integrate the answer being C with the question itself, we have to destroy the constraints of the solution and treat the duplicate 25% answers as one sum correct answer.
Do you choose to see the multiple choice answer space as an expression of the infinite space of potential free form answers? Was the answer to the question itself an expression of multiple choice probability or was it the answer from the free form answer space condensed into the multiple choice answer space?
The question demonstrates arriving at different answers between inductive and deductive reasoning. The answer depends on whether we are taking the answers and working backwards or taking the question and working forwards. The question itself forces the inductive reasoning strategy to falter at the duplicate answers, leading to deductive reasoning being the remaining strategy. Some may choose to say "there is no answer" in the presence of needing to answer a question that only has an answer because we are forced to pick one option, and otherwise would be invalid. Some may choose to point out it is obviously a paradox.

The answer is not available. The answer is 0 Percent. Each answer, if chosen, would be incorrect. If 0% was an answer, it would be the correct one despite being a 25% chance. Of course, if one 25% was there, that would be the correct answer.
- But if you did randomly choose the 0% option, you'd be correct. So if one of the possible answers was 0% the correct answer would be 25%.
  
  But it wouldn't be correct, so 0% would remain the answer.

This only produces a paradox if you fall for the usual fallacy that "at random" necessarily means "with uniform probability".
For example, I would pick an answer at random by rolling a fair cubic die and picking a) if it rolls a 1, b) on a 2, d) on a 3 or c) otherwise so for me the answer is c) 50%.
However, as it specifies that you are to pick at random the existence, uniqueness and value of the correct answer depends on the specific distribution you choose.

I argue it's still 25%, because the answer is either a,b,c, or d, you can only choose 1, regardless of the possible answer having two slots.
- Yup. And it says pick at random. Not apply a bunch of bullshit self mastubatory lines of thinking. Ultimately, 1 of those answers are keyed as correct, 3 are not. It's 25% if you pick at random. If you're applying a bunch of logic into it you're no longer following the parameters anyway.
  
  If you picked it randomly 100 times, would you be correct only 25% of time despite two choices being the same?
  It must be a 50% chance.
  But that would mean 50% is correct and....
  Correct answer: all the answers in the multiple choice are wrong
  
  You can just say "I don't understand probability (or the word 'if')" next time and save a whole bunch of effort.

Since two of them are the same, you have a 50% chance of picking something that is 33% of the possible answers. The other two, you have 25% chance of picking something that us 33% of the possible answers.
So 50%33% + 2 (33%*25%)= 33%
So your chances of being right is 33% cause there is effectively 3 choices.
- But that one answer has a 33% larger possibility of being chosen by random, than the remaining two.
  
  I covered that by multiplying it by 50% as it represents 50% of the choices.

There is absolutely no way it is 60%. Because you can never have 60% chances of picking anything particular when there are only 4 choices. Knowing this, the answer is either 25% or 50%. Two effective choices, so the answer is C, 50%.
- If C is the correct choice, then that is only one answer out of four that is correct, meaning you only had a 25% chance to answer correctly. You've created a logical paradox.
  25% occurs twice, so in reality there are only 3 outcomes from your pick. Since you know 25% is incorrect from this, that is 30% of the total answers, but also 50% of total options. Via this, you can conclude that both b and c are valid answers, depending on whether you view it in relation to outcomes or in relation to options. If you view the 3 outcomes, then you have a 60% chance of being right, but if you view the 4 options, you have a 50% chance of being right. Both 50% and 60% being accepted as anwswers solves the paradoxical nature of the question.
  
  the key word here is at random, you imagine a situation where you're doing it at random, but you're not actually answering randomly are you?
  
  If I'm choosing at random between 50% and 25%, then I have 50% chance to get 50%. It is random, but I eliminate the weird options.
  I do that sometimes.

100 **** percent, i'm all in!

Ahhhhhhhhhhhhhhhhh
- There's a reason I dropped probability at school.

- So then shouldn’t it be 100%?
  
  More like 0%

60%

B) 60% because I'm generally very lucky.

Can I take a 50/50 joker first?

Yes

Selecting not at random, A xor D must be correct, because the answer key can only have one correct answer so even duplicate right answers must also be wrong.
- It asked for whether the answer is correct not whether it lines up with the answer sheet.

I asked Google to roll a D4 and it rolled a 4. So my answer (correct or not) when following the directions in the question is the fourth one (D).