Hrm, it sounds like the teacher already knew the answer.Maybe stop wasting the time of the student then!?You're welcome.
No, copilot solve this testAnswer:To solve the expression e{\int_01 x2+x+1 \, dx} \), we first need to calculate the integral of \( x2+x+1 from 0 to 1.The integral of x2+x+1 \) is: \[ \int x2+x+1 dx = \frac{x3}{3} + \frac{x2}{2} + x + C Evaluating this from 0 to 1 gives us: \left[ \frac{x3}{3} + \frac{x2}{2} + x \right]_0^1 = \left( \frac{1}{3} + \frac{1}{2} + 1 \right) - \left( 0 + 0 + 0 \right) = \frac{11}{6} Now, we raise e to the power of this result: e^{\frac{11}{6}} This is the solution to the given expression. If you need a numerical approximation, e^{\frac{11}{6}} is approximately 4.953.
Hrm, it sounds like the teacher already knew the answer.
Maybe stop wasting the time of the student then!?
You're welcome.