I made a tool that transfers your reddit subscriptions to lemmy
I made a tool that transfers your reddit subscriptions to lemmy
Python script to transfer subreddit subscriptions to Lemmy - GitHub - induna-crewneck/Reddit-Lemmy-Migrator: Python script to transfer subreddit subscriptions to Lemmy
One thing that annoyed me about moving to Lemmy was that I'd lose my subreddits and that looking for and joining communities on Lemmy would be tedious. So (logically) I spent 2 days writing a script, that gets a list of your subreddits from your reddit account and looks for communities with the same name on Lemmy. It also joins those communites. So all you have to do is download, enter your credentials and you're done.
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How does this work when you have different communities on different instances?
It tries to subscribe to the one on lemmy.world as well as the most subscribed one on any instance according to lemmy.world.
You can access all instances from whichever server you are signing in from. Or am I misunderstanding your question?
They probably mean duplicate communities on different instances.
Why would that be an issue?
because it is not unequivocal mapping and he asks how you deal with the situation where you have 10 possible replacements. do you just sign to all of them?
Because some of these communities are more official than others. For example, I modded /r/simpleliving and made !simpleliving@lemmy.ml, but !simpleliving@lemmy.world also exists. It would be a bit annoying if users were directed to the less-active and less-official community over the one I made just because it happens to be on lemmy.world.
That's a fair point. In this case your lemmy.ml community would also be subscribed to, if it's any consolation.
How does this work if lemmy.world isn't your home instance? Will the same local community + most subscribed federated community rule apply?
Your home instance doesn't change this script's behavior as is. Works regardless, though.
If you want, you can do a search and replace of "lemmy.world" with "lemmyserver" in the code.