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Well, with those numbers, it's easy math. :)
V=5*10^2*10
5,000. 5,000 what though?
Even with a proper π value, it still doesn't make sense... 3,141.59265359
What? Its just the volume, without units. What part of it doesn't make sense?
Well, a r=10 and h=10 doesn't mean much without units. 10 what? Feet? Meters? Inches? CM?
Let's take the OG numbers and assume feet, so 5,000 cubic feet. That's not a useful volume measurement.
1 cubic foot of water = 7.48052 gallons
So 5,000 cubic feet of water = 37,402.6 gallons. That's a viable volume measurement.
1 cubic meter = 1,000 liters.
5,000 cubic meters = 5,000,000 liters.
Well, a r=10 and h=10 doesn't mean much without units. 10 what? Feet? Meters? Inches? CM?
Its not supposed to mean anything, it's about the equation not about the end result. We're not calculating an actual cilinder
If we're not calculating something useful, then why are we here and not in the library learing about the universe?
Better question: What curvature of space is necessary for the apparent value of π to be 5?
If we're not calculating something useful, then why are we here and not in the library learing about the universe?
We're learning maths, which is arguably the foundation of the universe.
Better question: What curvature of space is necessary for the apparent value of π to be 5?
I'm afraid that that is beyond the comprehension of my human existence
Better question: What curvature of space is necessary for the apparent value of π to be 5?
~~honestly I don't know if there is any way to measure curvature of space , but its slightly more curved than the surface of a ball (where π=4.712)~
edit : its more complex than that and topology of non euclidean spaces hurts
Kind of curious how you got that value. I think the ratio of circumference to diameter ("pi") is actually smaller in spherical geometry, in the most extreme case (the equator) it's just 1. You could say "pi = 5" for circles of a specific radius in hyperbolic geometry, I guess.
my mistake was using the sum of angles in a triangle which was kinda dum but whatever . I also tried calculating via the circumstance of a circle placed at a pole where π was 20x smaller for the case I was using but its not linear so I looked deeper which was a big mistake .
BTW the ratio of circumstance to radius for a circle which is also an equator of the space is ¼ not 1 (r=½π₀ , C=2π₀) .
BTW the ratio of circumstance to radius for a circle which is also an equator of the space is ¼ not 1 (r=½π₀ , C=2π₀) .
I think you mean 4, which makes the ratio of circumference to diameter 2 (either way, no idea how I messed up that one).
oopsie :3
Better question: What curvature of space is necessary for the apparent value of π to be 5?
I tried to approach an answer and I am leaving this comment to warn others not to follow my path , topology of non euclidean spaces hurts
The unit is unit.
The math doesn’t care, and what you’re on about only really matters if the units don’t start as all the same or if you start converting between things.
Five thousand cubic units
Literally the correct answer. Must be a bunch of engineers in this thread.
No, engineers wouldn't have a problem with this. This dude is just some rando that has no idea what he's whinging about
Just calculating a cylinder that may or may not have an m&m minis tube stuck on it