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I'll be drying the silver out and weighing it sometime in the next couple days. Closest guess when I do gets bragging rights! (And absolutely nothing else)

The scale was zeroed with the beaker empty, and it contains only water and silver (and a trace amount of copper nitrate). If you have a strategy behind your guess, please do share it!

47 comments
  • 250ml solution (mostly water on top) = 250g

    700g (if 700ml water) - 250g = 450ml silver slurry

    450ml silver powder weight (dry) = 1800g

    1464g (total) - 250g (excess water) = 1214g

    450ml slurry = 1214g slurry

    1800g (dry silver) - 1214g (silver slurry) = 516g (516ml water in slurry)

    1464g (total) - 516g (water) = 948g silver powder.

    I always miss something obviously stupid when doing math in public. However, it sounds suspiciously close to a 1kg starting weight of silver though.

    • I always miss something

      Yes, in the very last line, it made no sense anymore (and I bet you felt it in your gut).

      It should not be:

      1464g (total) - 516g (water) = 948g silver powder.

      but rather:

      1214g (silver slurry) - 516g (water in slurry) = 698g silver powder.

      • Damnit. I edited with that correction, but deleted the edit, cause who the fuck knows why. Was kind of in a rush at the time, and didn't think I would have been silly enough to miss the 250g.

        Good cach and yeah, I felt it.

    • 1800g (dry silver) - 1214g (silver slurry) = 516g (516ml water in slurry)

      What? Why? I'm kind of sure that this is wrong (subtracting (water + silver) from silver can't get you water, you could get (silver - water) at best) but I'm interested in the reasoning here because it short circuit my brain.

      • I'll walk through it again, as you are probably right, and I can find the mistake.

        1800g is the estimate weight of 450gml silver powder.

        The total weight is 1464g.

        There is 250ml (g) of water at the top of the container, which we subtract from the total weight, leaving 1214g of a silver/water slurry.

        1800g should be the weight

        1214g is the weight.

        (Here is the mistake) The weight difference is 516g, which is the weight of the missing silver in the slurry, not the weight of the water in the slurry.

        So, I would need to convert 516g to an approximate volume of silver powder. Since we have volume, we can now compute the weight of the water in the slurry.

  • 1102g - took a stab at the density of micron-sized silver powder, the volume, then arbitrarily knocked off 30% for the saturation in water 🤷

  • 1026g. Based on the amount of visible water volume, and a guess of more above that subtracted from the total weight.

47 comments