At least you got a grease gun
At least you got a grease gun
At least you got a grease gun
Oh... Oh dear...
That's... not true
22 = 4 32 = 9
(22 +32) = 13
(2 + 3)2 = 52 = 25
13 != 25
I'm pretty sure that's part of the joke.
It's missing 2*abe
it’s true in ℤ/2ℤ
(a+b)^2=a^2 + b^2 + 2ab
By the cancellation law
a^2 + b^2 + 2ab = a^2 + b^2
only when
2ab = 0
So either a=0
or b=0
erm 13! ≠ 25
True when a and b are orthogonal.
Just use the damn Pascal's triangle!
1 = 1 * 1 = (a+b)^0 1 1 = 1a + 1b = (a+b)^1 1 2 1 = 1a^2 + 2ab + 1b^2 = (a+b)^2 1 3 3 1 = 1a^3 + 3(a^2)b + 3a(b^2) + 1b^3 = (a+b)^3
By the way, I have submitted maths homework that had me continue it up to layer 25. The exercise didn't explicitly state we should use the binomial formula, so why work smart when you can work hard?
(To be fair I just used WolframAlpha to get the values. Had to write down all terms still and do some calculations.)
Self explanatory
All I know is Left Add Right Subtract.
But I do have a pretty rad cannon.
(a-b)(a+b) = a2 + b2
(a+ib)(a-ib) = a2 + b2