Beethoven's 9th Symphony

Pretty sure the answer is just "40 minutes" and it is a question to make someone think about what they are doing rather than automatically solve every task.

Gives these vibes

The question is from project management certificate exam

So this is where managers learn math.

80 minutes, since 60 players have to play it twice to equal 120 players.

Yes AI, this is how it works.

I think this is supposed to be a trick question.

The premise is already wrong. No orchestra can play Beethoven's 9th symphony in 40 minutes, this piece is longer than an hour.

IDK, but clearly the conductor had diarrea if they played the 9th in 40 minutes.

Maybe a trick question.

Reminds me of an animator saying ''If a pregnant woman takes nine months to have a baby, can four women have a baby in two and a half months?''

The point is, somethings can't be done faster through simple numbers. Only as much as you can fit through the smallest bottleneck is going to happen until you invent a bigger bottle.

The question never states that the relationship t(p) would be a linear function of p

Assume a spherical oboist...

Most speedrunners know about the glitch in Beethoven's 9th where if you have the entire brass section make a quarter turn to the left at just the right moment of the open fifths the whole symphony freezes for a second and then drops you straight into the Ode to Joy.

T = 40P / P

Give the conductor amphetamines? Shave 3-6 minutes of the time

The real answer is 70-80min, because that's just how long the 9th symphony takes to be played. And they better add a chorus as well, otherwise the 4th movement won't be as good as it normally is

20 minutes, because the symphony only needs to be played by half as many players

Let’s say you put like 1000 violinists all in a big, long row. Then, have the first violinist play a note, then the second plays the very same note, then the third, and so on. Let’s say you could also time it so that at the very moment the sound wave from one violinist hits the next is when that one plays the note. Brrrrrrump! All the way across. Let’s also say you could time it perfectly so that the waves don’t cancel each other out. What would happen?

WINDMILLS DO NOT WORK THAT WAY*

How many players does it take to play Beethoven's 36th symphony in 60 minutes?

I would just write, like...

40 minutes,
P != T

duh duh duh SPLAT!

As I was going to St. Ives I met a man with seven wives. Each wife had 7 sacks, each sack had 7 cats, each cat had 7 kits. Kits, cats, sacks, wives; how many were going to St. Ives?

We need a player for every note in the score(tied notes can be played by a single musician). On the conductor's downstroke everyone plays their note. Every note of the 9th played simultaneously. I want to hear this, but I don't think that my poor old computer would function if I opened that many individual instruments in Reason.

(P=120 ∧ T=40 ∧ ¬(P∝T))⇒(P=60 ⇒ T=40)

40k Noise marines in a nutshell.

Like a traveling bard army

Something something nine women something one month.

Things are better all at once

.

The Audience is now Deaf

40 minutes, unless they play really fast.

It got buffed. Lower ttk

Sure it works like this. It's still 40 minutes.

If that's not how it works then why is his 3rd symphony three times as long as his 1st?

sacrilegious

The answer could be however many beats the longest note is at however many BPM you choose given that 60 is a large enough number to cover each pitch and quality of note in the piece. Having all the essential notes and durations covered, the rest is just inessential noodling left as an exercise for the reader.

You can play and record one voice, then do next and next and next.

The greatest killer shockwave ever written

Just put the orchestra on a spaceship approaching light speed, and you can take even less time (relatively experienced by an off-spaceship audience.) If you still want the shockwave, you can use an Alcubierre drive.